JEE Main 2024 Mathematics question
Let A(−2, −1), B(1, 0), C(α, β) and D(γ, δ) be the vertices of a parallelogram ABCD. If the point C lies on 2x − y = 5 and the point D lies on 3x − 2y = 6, then the value of |α + β + γ + δ| is equal to .
Answer: 32
Solution
The diagonals bisect each other: the midpoint of AC equals the midpoint of BD, giving (α − 2)/2 = (1 + γ)/2 and (β − 1)/2 = δ/2, i.e. γ = α − 3 and δ = β − 1. C lies on 2x − y
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account