JEE Main 2024 Physics question
A force is represented by F = ax² + . Where x = distance and t = time. The dimensions of b²/a are :
Answer: (A)
Solution
[a] = [F/x²] and [b] = [F/√t], so [b²/a] = [F²/t]/[F/x²] = [Fx²/t] = [MLT⁻²·L²/T] = [ML³T⁻³].
A force is represented by F = ax² + . Where x = distance and t = time. The dimensions of b²/a are :
[a] = [F/x²] and [b] = [F/√t], so [b²/a] = [F²/t]/[F/x²] = [Fx²/t] = [MLT⁻²·L²/T] = [ML³T⁻³].