JEE Main 2024 Physics question
If the wavelength of the first member of Lyman series of hydrogen is λ. The wavelength of the second member will be
Answer: (D)
Solution
For the first member 1/λ = R(1 − 1/4) = 3R/4. For the second member 1/λ′ = R(1 − 1/9) = 8R/9. So λ′/λ = (3/4)/(8/9) = 27/32.