JEE Main 2024 Physics question
If the percentage errors in measuring the length and the diameter of a wire are 0.1% each. The percentage error in measuring its resistance will be:
Answer: (C)
Solution
R = 4ρℓ/(πD²), so ΔR/R = Δℓ/ℓ + 2ΔD/D = 0.1 + 2(0.1) = 0.3%.