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JEE Main 2024 Physics question

PhysicsOscillationsJEE Main 2024

A particle performs simple harmonic motion with amplitude A. Its speed is increased to three times at an instant when its displacement is 2A/3. The new amplitude of motion is nA/3. The value of n is .

Answer: 7

Solution

v = ω√(A² − x²). Before: v = ω√(A² − 4A²/9). After tripling the speed at the same x:

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Question ID VK-017399