JEE Main 2024 Physics question
A small square loop of wire of side ℓ is placed inside a large square loop of wire of side L (L = ℓ²). The loops are coplanar and their centres coincide. The value of the mutual inductance of the system is √x × 10⁻⁷ H, where x = .
Answer: 128
Solution
For the current i in the large loop, the field at the centre is B = 4[(μ₀i/(4π(L/2)))√2] = 8√2 × 10⁻⁷ i/L. The flux
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