JEE Main 2024 Chemistry question
Number of moles of methane required to produce 22 g CO₂(g) after combustion is x × 10⁻² moles. The value of x is .
Answer: 50
Solution
CH₄ + 2O₂ → CO₂ + 2H₂O. 22 g of CO₂ is 0.5 mol, so 0.5 mol of methane is required = 50 × 10⁻² mol.