JEE Main 2024 Chemistry question
One Faraday of electricity liberates x × 10⁻¹ gram atom of copper from copper sulphate. x is .
Answer: 5
Solution
Cu²⁺ + 2e⁻ → Cu, so 2 F liberates 1 gram atom of Cu and 1 F liberates 0.5 gram atom = 5 × 10⁻¹. So x = 5.