JEE Main 2024 Mathematics question

Mathematics Function JEE Main 2024

If , x ≠ 2/3 and (fof)(x) = g(x), where g : ℝ − {2/3} → ℝ − {2/3}, then (gogog)(4) is equal to

(A)19/20
(B)4Correct
(C)−19/20
(D)−4

Answer: (B)

Solution

(fof)(x) = [4(4x + 3)/(6x − 4) + 3]/[6(4x + 3)/(6x − 4) − 4] = (34x)/(34) = x. So g(x) = x and (gogog)(4) = 4.

Question ID VK-017439