JEE Main 2021 Chemistry question

Identify the elements X and Y using the ionisation energy values given below : Ionization energy (kJ/mol): 1st, 2nd X: 495, 4563 Y: 731, 1450

• (A)X = Na ; Y = MgCorrect
• (B)X = Mg ; Y = F
• (C)X = Mg ; Y = Na
• (D)X = F ; Y = Mg