For the reaction A(g) B(g) at 495 K, _rG^0 = –9.478 kJ mol ^ -1 . If we start the reaction in a closed...

Question

For the reaction A(g) B(g) at 495 K, _rG^0 = –9.478 kJ mol ^ -1 . If we start the reaction in a closed container at 495 K with 22 millimoles of A, the amount of B in the equilibrium mixture is ________ millimoles. (Round off to the Nearest Integer). [R = 8.314 J mol ^ -1 K^ -1 ; ln 10 = 2.303]

Accepted Answer

20

JEE Main 2021 Chemistry question

Solution