Let y = mx + c, m 0 be the focal chord of y^2 = –64x, which is tangent to (x+10)^2+y^2=4. Then, the value...

Question

Let y = mx + c, m > 0 be the focal chord of y^2 = –64x, which is tangent to (x+10)^2+y^2=4. Then, the value of 4 2(m+c) is equal to _________.

Accepted Answer

34

JEE Main 2021 Mathematics question