JEE Main Mathematics question
If (1+x)^n={}^nC_0+{}^nC_1x+{}^nC_2x^2+\ldots+{}^nC_nx^n, then \frac{{}^nC_1}{{}^nC_0}+\frac{2\,{}^nC_2}{{}^nC_1}+\frac{3\,{}^nC_3}{{}^nC_2}+\ldots+\frac{n\,{}^nC_n}{{}^nC_{n-1}} is equal to
Answer: (C)
Solution
Since , the term is
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