If the roots of 10x^3-nx^2-54x-27=0 are in harmonic progression, then 'n' equals

JEE Main Mathematics question

If the roots of are in harmonic progression, then '' equals

Answer: 9

The roots satisfy and ; HP gives , so pq+qr+rp=3pr=-\frac{27}5 and . Then , and substituting in the equation:

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Question ID VK-021754