JEE Main 2021 Chemistry question

ChemistryElectrochemistryJEE Main 2021

For the cell Cu(s) |(aq) (0.1M) || (aq) (0.01 M) | Ag(s) the cell potential = 0.3095 V. For the cell Cu(s) |(aq) (0.01 M) || (aq) (0.001 M) | Ag(s), the cell potential = V. (Round off the Nearest Integer). [Use : = 0.059]

Answer: 28

Solution

Question ID VK-022959