JEE Main 2021 Chemistry question

ChemistrySolutionsJEE Main 2021

40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is ——— K. (Nearest integer) [Given : = 1.86 K kg ; Density of water = 1.00 g ; Freezing point of water = 273.15 K]

Answer: 271

Solution

Question ID VK-023134