JEE Main 2021 Chemistry question

Consider the following cell reaction Cd_{(s)}+Hg_2SO_{4(s)}+\frac{9}{5}H_2O_{(l)}\rightleftharpoons CdSO_4.\frac{9}{5}H_2O_{(s)}+2Hg_{(l)} The value of is 4.315 V at 25°C. If = –825.2 kJ , the standard entropy change in J is [Given : Faraday constant = 96487 C ]