JEE Main 2021 Chemistry question
The rate constant of a reaction increases by five times on increase in temperature from 27°C to 52°C. The value of activation energy in kJ is (Rounded-off to the nearest integer) [R = 8.314 J ]
Answer: 52
The rate constant of a reaction increases by five times on increase in temperature from 27°C to 52°C. The value of activation energy in kJ is (Rounded-off to the nearest integer) [R = 8.314 J ]