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JEE Main 2021 Mathematics question

MathematicsContinuity and DifferentiabilityJEE Main 2021

A function f is defined on [–3, 3] as Bracket argument to \\ must be a dimensionf(x)=\begin{cases}\min\{|x|,2-x^2\}, & -2\le x\le2\\[|x|], & 2<|x|\le3\end{cases} where [x] denotes the greatest integer x. The number of points, where f is not differentiable in (–3, 3) is .

Answer: 5

Solution

Question ID VK-023341