JEE Main 2021 Chemistry question
Consider the cell at 25°C Zn | (aq), (1 M) || (aq), (aq) |Pt(s) The fraction of total iron present in the cell at the cell potential of 1.500 V is x. The value of x is. (Nearest integer) [Given := = 0.77V, =–0.76V]
Answer: 24