Let y = y(x) be solution of the differential equation dy dx =1+xe^ y-x , - 2

Question

Let y = y(x) be solution of the differential equation dy dx =1+xe^ y-x , - 2<x< 2, y(0)=0, then, the minimum value of y(x), x (- 2, 2) is equal to :

Accepted Answer

(D)

JEE Main 2021 Mathematics question