JEE Main 2021 Chemistry question
Emf of the following cell at 298 K in V is x . Zn| (0.1 M) || (0.01 M) | Ag. The value of x is . (Rounded off to the nearest integer) [Given ; = –0.76 V; = +0.80 V; = 0.059]
Answer: 147
Emf of the following cell at 298 K in V is x . Zn| (0.1 M) || (0.01 M) | Ag. The value of x is . (Rounded off to the nearest integer) [Given ; = –0.76 V; = +0.80 V; = 0.059]