JEE Main 2022 Physics question
A projectile is projected with velocity of 25 m/s at an angle with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of will be [use g = 10 ]
Answer: (4)
Solution
The inclination is zero at the top, so t = 25 (time to the highest point). The range is (25)^{2}(2\sin\cos$ θ )/g =
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