JEE Main 2022 Physics question
A Carnot engine whose heat sinks at 27°C, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency?
Answer: (2)
Solution
Initially 1/4 = 1 − 300/, so = 400 K. For an efficiency of 1/2: $1/2 =
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