JEE Main 2022 Physics question
From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the rest from the same location, will reach the ground in s.
Answer: 3
Solution
With the tower height h and the common throwing speed u: (thrown up) and (thrown down), where s and $ =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account