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JEE Main 2022 Chemistry question

ChemistryThermodynamicsJEE Main 2022

. At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (–) J . (Nearest integer) [Given: ln 1.35 = 0.3 and R = 8.3 J ]

Answer: 747

Solution

Starting from 1 mol of with 50% dissociation: 0.5 mol and 0.75 mol , so the total is 1.25 mol and at 1 atm the partial

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Question ID VK-024121