JEE Main 2022 Physics question
An electric bulb is rated as 200 W. What will be the peak magnetic field at 4 m distance produced by the radiations coming from this bulb? Consider this bulb as a point source with 3.5% efficiency.
Answer: (2)
Solution
The intensity at 4 m is $I = (200 × 3.5/100)/(4π × 16) =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account