JEE Main 2022 Physics question
A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 . The maximum height reached by the body during its motion is m. (use g = 10 )
Answer: 20
Solution
The horizontal component stays u cos45°. After 2 s the vertical component is u sin45° − 20. The speed 20 m/s then gives \sqrt{2}$ +
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