JEE Main 2022 Chemistry question
Hex-4-ene-2-ol on treatment with PCC gives 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is
Answer: (3)
Solution
CH_{3}-CH(OH)-CH_{2}-CH=CH-CH_{3} is oxidised by PCC to the methyl ketone CH_{3}COCH_{2}CH=CHCH_{3} (A). Sodium hypoiodite (the iodoform reaction)
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