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JEE Main 2022 Chemistry question

ChemistryEquilibriumJEE Main 2022

dissociates as . 5 moles of are placed in a 200 litre vessel which contains 2 moles of and is maintained at 600 K. The equilibrium pressure is 2.46 atm. The equilibrium constant for the dissociation of is . (nearest integer) (Given: R = 0.082 L atm ; Assume ideal gas behaviour)

Answer: 1107

Solution

At equilibrium the moles are , , and , so = 7 + x. P = nRT/V: , so 7 + x = 10 and x = 3.

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Question ID VK-024212