Test SeriesFree PYQsExamsPricing

JEE Main 2022 Chemistry question

ChemistryElectrochemistryJEE Main 2022

The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1750 . If the conductivity of 0.01 M KCl solution at 298 K is S , then the cell constant of the conductivity cell is .

Answer: 266

Solution

Conductivity = cell constant/resistance, so the cell constant = $κ R

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-024213