JEE Main 2022 Mathematics question

MathematicsThree Dimensional GeometryJEE Main 2022

Let the points on the plane P be equidistant from the points (−4, 2, 1) and (2, −2, 3). Then the acute angle between the plane P and the plane 2x + y + 3z = 1 is

Answer: (3)

Solution

The locus of points equidistant from the two given points is , which simplifies to 3x −

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-024234