JEE Main 2022 Chemistry question
The pressure of a moist gas at 27°C is 4 atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is atm. (Nearest integer) (Given: The vapour pressure of water at 27°C is 0.4 atm.)
Answer: 22
Solution
The pressure of the dry gas is 4 − 0.4 = 3.6 atm. When the volume is doubled at constant temperature it becomes 1.8 atm $ =
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