JEE Main 2022 Chemistry question
The cell potential for Zn|Zn^{2+}(aq)||Sn^{x+}|Sn is 0.801 V at 298 K. The reaction quotient for the above reaction is . The number of electrons involved in the given electrochemical cell reaction is . (Given : = −0.763 V, = +0.008 V and 2.303RT/F = 0.06 V)
Answer: 4
Solution
E°_cell = E°(cathode) − E°(anode) = 0.008 − (−0.763) = 0.771 V. By the Nernst equation,
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