JEE Main 2022 Mathematics question
The curve + cx + 5 touches the x-axis at the point P(−2, 0) and cuts the y-axis at the point Q, where is equal to 3. Then the local maximum value of y(x) is :
Answer: (1)
Solution
The curve passes through (−2, 0): −8a + 4b − 2c + 5 = 0, i.e. 8a − 4b + 2c = 5. It touches the x-axis at (−2, 0), so . At x = 0 the slope is . Solving
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