JEE Main 2022 Mathematics question
If the sum and the product of mean and variance of a binomial distribution are 24 and 128 respectively, then the probability of one or two successes is
Answer: (3)
Solution
np + npq = 24 and (np)(npq) = 128. Solving, p = q = 1/2 and n = 32. Then $P(X = 1) +
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