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JEE Main 2022 Mathematics question

MathematicsCircleJEE Main 2022

Let the equation of two diameters of a circle be 2px − y = 1 and 2x + py = 4p. Then the slope m (0, ) of the tangent to the hyperbola passing through the centre of the circle is equal to .

Answer: 2

Solution

The centre (1, −f) lies on both diameters: 2p + f − 1 = 0 and 2 − pf − 4p = 0. Eliminating p gives , so f = 0 or f = −3 (and the centre is (1, 0) or (1, 3)). The tangent to

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Question ID VK-024831