JEE Main 2022 Mathematics question
Let the eccentricity of the hyperbola be 5/4. If the equation of the normal at the point (, 12/5) on the hyperbola is , then is equal to .
Answer: 85
Solution
With e = 5/4, , so b = 3a/4. The point (, 12/5) lies on the hyperbola: − 144/(25 · , which gives a = 8/5 and b = 6/5. The normal at (, ) is
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