JEE Main 2022 Chemistry question

In a cell, the following reactions take place: Fe^{2+} \to Fe^{3+} + e^{-} (E^{\circ}(Fe^{3+}/Fe^{2+}) = 0.77 V) and V). The standard electrode potential for the spontaneous reaction in the cell is V at 298 K. The value of x is . (Nearest Integer)