JEE Main 2022 Mathematics question
Let f(x) be a polynomial function such that + f″(x) = . Then, the value of is equal to :
Answer: (1)
Solution
Let + dx + e. Matching the coefficients in + f″ = gives a + 5 = 0, b + 4a + 20 = 0, c + 3b + 12a = 0, d + 2c + 6b = 0 and e + d + 2c =
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