Test SeriesFree PYQsExamsPricing

JEE Main 2022 Mathematics question

MathematicsCircleJEE Main 2022

Let the abscissae of the two points P and Q be the roots of − rx + p = 0 and the ordinates of P and Q be the roots of − sx − q = 0. If the equation of the circle described on PQ as diameter is , then 2r + s − 2q + p is equal to .

Answer: 7

Solution

The circle on PQ as diameter is , i.e. . Here = r/2, = p/2,

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-025007