JEE Main 2022 Physics question
A velocity selector consists of electric field and magnetic field with B = 12 mT. The value of E required for an electron of energy 728 eV moving along the positive x-axis to pass undeflected is (Given, mass of electron = kg)
Answer: (1)
Solution
The electron passes undeflected when v = E/B, and . So \sqrt{2K/m}10^{-3}\sqrt${(2
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