A uniform heavy rod of mass 20 kg, cross sectional area 0.4 m^ 2 and length 20 m is hanging from a fixed...

Question

A uniform heavy rod of mass 20 kg, cross sectional area 0.4 m^ 2 and length 20 m is hanging from a fixed support. Neglecting the lateral contraction, the elongation in the rod due to its own weight is x 10^ -9 m. The value of x is _____. (Given Young's modulus Y = 2 10^ 11 Nm^ -2 and g = 10 ms^ -2 )

Accepted Answer

25

JEE Main 2022 Physics question

Solution

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