JEE Main 2022 Physics question
When a car is approaching the observer, the frequency of horn is 100 Hz. After passing the observer, it is 50 Hz. If the observer moves with the car, the frequency will be x/3 Hz where x = .
Answer: 200
Solution
Approaching: v/(v − . Receding: v/(v + . Dividing, 2 = (v + /(v − , so = v/3. Then v/(2v/3) =
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