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JEE Main 2022 Physics question

PhysicsAtomsJEE Main 2022

In the hydrogen spectrum, be the wavelength of first transition line of Lyman series. The wavelength difference will be the wavelength of transition line of Paschen series and that of transition line of Balmer series where a = .

Answer: 5

Solution

First Lyman line : − 1/4) = 3R/4, so = 4/(3R). Third Paschen line : = R(1/9 − 1/36) = R/12, so = 12/R. Second

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Question ID VK-025132