JEE Main 2022 Chemistry question
When 800 mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is M. (Nearest integer) (Molar mass of nitric acid is 63 g )
Answer: 54
Solution
The initial moles of mol = 25.2 g. After evaporation 25.2 − 11.5 =
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