If dy/dx + 2y tan x = sin x, 0 < x < /2 and y( /3) = 0, then the maximum value of y(x) is :

JEE Main 2022 Mathematics question

If dy/dx + 2y tan x = sin x, and , then the maximum value of y(x) is :

Answer: (1)

The integrating factor is x dx} = . So y x dx = x tan x dx = sec x + C. With $y(π

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Question ID VK-025174