JEE Main 2022 Physics question
Not in JEE or NEET syllabus
A sinusoidal wave y(t) = 40 is amplitude modulated by another sinusoidal wave x(t) = 20 . The amplitude of minimum frequency component of modulated signal is:
Answer: (4)
Solution
The modulated signal is s(t) = [1 + 20 . Expanding, \sin(10^{7}\cos(10^{7}10^{3}\cos$
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