JEE Main 2022 Physics question
A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is Hz.
Answer: 152
Solution
Let the first frequency be . Then $ν _{20} = ν _{1} + 4 × 19 = ν
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account