JEE Main 2022 Mathematics question

MathematicsSequence and SeriesJEE Main 2022

Let Extra open brace or missing close braceA = \Sigma \_{i=1}^{10}\Sigma \_{j=1}^{10}\min {i, j} and Extra open brace or missing close braceB = \Sigma \_{i=1}^{10}\Sigma \_{j=1}^{10}\max {i, j}. Then A + B is equal to .

Answer: 1100

Solution

For every ordered pair (i, j), min{i, j} + max{i, j} = i + j. So $A + B = Σ

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-025372